Question

Translate to a system of equations and solve.

A 40% antifreeze solution is to be mixed with a 70% antifreeze solution to get 240 liters of a 64% solution. How many liters of the 40% and how many liters of the 70% solutions will be used?

1) 40% solution_______________ L

2) 70% solution________________ L

Answer 1

let amount of 40% solution be x ,

=>amount of 70% solution =240-x

40% antifreeze solution is mixed with a 70% antifreeze solution to get 240 liters of a 64% solution

=>(40_/100)x+(70_/100)(240-x) =(64_/100)240

=>0.4x +168-0.7x =153.6

=>0.7x -0.4x = 168-153.6

=>0.3x =14.4

=>x=14.4_/0.3

=>x=48

amount of 70% solution =240-48= 192

1)amount of 40% solution is 48 L

2)amount of 70% solution is 192 L

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