Given the second order initial value problem y′′−3y′=12δ(t−2), y(0)=0, y′(0)=3y″−3y′=12δ(t−2), y(0)=0, y′(0)=3Let Y(s)Y(s) denote the Laplace transform of yy. Then
Y(s)=Y(s)= .
Taking the inverse Laplace transform we obtain
y(t)=
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