How many pounds of candy that sells for $0.64 per lb must be mixed with candy that sells for $1.19 per lb to obtain 9 lb of a mixture that should sell for $0.91 per lb?
Let, the number of pounds of candy 1 be x
Selling price of candy 1 is $0.64/lb
Total amount for which candy 1 is sold is 0.64x
The number of pounds of candy 2 be 9-x
Selling price of candy 2 is $1.19/lb
Total amount for which candy 2 is sold is 1.19(9-x)
Total amount for which the mixture is sold is 9(0.91)=$8.19
Equate the selling price of each
That is
Hence, 4.6182 pounds of candy 1 must be mixed with 4.3818 pounds of candy 2 to get a mixture of 9 pounds that sells for $0.91/lb
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