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Find the equation of the tangent line to the graph of the function f(x)=(x^2+8)(x−2) at the...

Find the equation of the tangent line to the graph of the function f(x)=(x^2+8)(x−2) at the point (1,−9).

I thought it was re-writen as (2x^2 + 8)(x-2) then plugging in 1 for x and solving. I came up withit in slope form y = -20x - 1 but says im wrong. What steps did i miss?

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