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Suppose that ff is a Riemann integrable function on [0,2][0,2] and that ∫20f(x)dx=5∫02f(x)dx=5. Suppose further that...

Suppose that ff is a Riemann integrable function on [0,2][0,2] and that ∫20f(x)dx=5∫02f(x)dx=5. Suppose further that AA is a function such that if 0≤a≤20≤a≤2 then the average value of ff on the interval [0,a][0,a] is given by A(a)A(a). Find a formula for the average value of ff on [a,2][a,2] using AA.

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