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If an object is propelled upward from a height of s feet at an initial velocity...

If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=−16t^2+vt+s, where h is in feet. If the object is propelled from a height of 1212 feet with an initial velocity of 9696 feet per second, its height h is given by the equation h =minus−16t^2+96 +12. After how many seconds is the height 120 feet?

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