Question

If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=−16t^2+vt+s, where h is in feet. If the object is propelled from a height of 1212 feet with an initial velocity of 9696 feet per second, its height h is given by the equation h =minus−16t^2+96 +12. After how many seconds is the height 120 feet?

Answer #1

A ball is thrown vertically upward from a height of 5 ft with an
initial velocity of 83 ft/s. The distance s (in feet) of the ball
from the ground after t seconds is s = s(t) = 5 + 83t − 16t^2. (a)
What is the velocity v, in feet per second, of the ball after 2
seconds?
(b) When, in seconds, will the ball reach its maximum height?
(Round your answer to one decimal place.)
(c) What is...

An object is launched upward from a platform so that its height
(in feet) above the ground t seconds after it is launched
is given by the function h(t)=-16t^2
+160t+176.
a. When does the object reach its maximum height? What is the
maximum height?
b. When does the object hit the ground?
c. What is the domain and range of this
function (given the context)?
d. Sketch an accurate graph of this function in an
appropriate window. Mark on your...

A
ball is thrown directly upward from a height of 3 ft with an
initial velocity of 20 ft/sec. the function s(t) = -16t^2+20t+3
gives the height of the ball, in feet, t seconds after it has been
thrown. Determine the time at which the ball reaches its maximum
height and find the maximum height.

An object is thrown upward at a speed of 128 feet per second by
a machine from a height of 13 feet off the ground. The height (h)
of the object after (t) seconds can be found using the equation
h(t)=−16t2+128t+13
When will the height be 269 feet? and When will the object reach
the ground?

An object is thrown upward at a speed of 184 feet per second by a
machine from a height of 8 feet off the ground. The height hh of
the object after tt seconds can be found using the equation
h=−16t2+184t+8
When will the height be 528 feet?
When will the object reach the ground?

A flare is launched upward with an initial velocity of 80 ft/sec
from a height of 224 ft. Its height in feet
after t seconds is given by h t t t ( ) = − + + 16 80 224. 2 How
long will it take the flare to reach the ground?

An object is dropped from 43 feet below the tip of the pinnacle
atop a 367-ft tall building. The height h of the object after t
seconds is given by the equation
h=-16t^2+324. Find how many seconds pass before the object
reaches the ground.

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of 120 feet per second. The height s in feet can be expressed as a
function of time t in seconds by s(t)=85t-16t^2 a. when does the
ball reach its maximum height b. what is the maximum height c. when
does the ball hit the ground
12. a farmer has 2800 feet of fencing material with which to
enclose a rectangle field that borders a straight stream....

Use the position equation given below, where s represents the
height of the object (in feet), v0 represents the initial velocity
of the object (in feet per second), s0 represents the initial
height of the object (in feet), and t represents the time (in
seconds), as the model for the problem. s = ?16t2 + v0t + s0 An
aircraft flying at 300 feet over level terrain drops a supply
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the velocity (in feet/second) of a projectile t seconds after it
is launched from a height of 10 feet. is given by v(t)= -15.1t+145.
approximate its height 3 seconds using 6 rectangles it is
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