Question

Sketch the region enclosed by x = 56 − y^ 2 and x = − y . Then find the area of the region.

Answer #1

Sketch the region enclosed by y = sin ( π /3 x ) and y =( − 2
/3) x + 2 . Then find the area of the region.

Sketch the region enclosed by the curves and find its area.
y=x,y=4x,y=−x+2
AREA =

Sketch the region enclosed by the given curves and find its
area:
a)y=x^2-4
b)y=x+2 1<=x<=4

Sketch the region enclosed by the curves y=x(1-x) and y=-9x+9
then compute its area.

Sketch the region enclosed by the given curves. y = |9x|, y = x2
− 10
And find the area

Find the area of the region enclosed by y = (x + 2)^2 , y = 1 x
+ 2 , x = − 3/2 , and x = 1.

Sketch the region enclosed by the given curves. Decide whether
to integrate with respect to x or y. Draw a
typical approximating rectangle and label its height and width. (Do
this on paper. Your instructor may ask you to turn in this
graph.)
y=4+2sqrtx , y=8/2+x/2
Then find the area S of the region.
S=

Let X be the region bounded by y=x and y=x^2.
Sketch the region X and find the area. Explain

Find the area of the region enclosed by the curves x=2y and
4x=y^2

Sketch the region enclosed by the given curves. Draw a typical
approximating rectangle and label its height and width and shade
the area. Lastly, find its area.
1.) y = 3x + 2, y = 14 −
x2, x =
−1, x = 2
2.) y = 9 cos(πx), y = 8x2 −
2
3.) y = |5x|, y = x2 − 6

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