1) Find the net change in f(x) on 0≤x≤3 where: f'(x)=(x^3)/√(36−x^2) Express your answer in exact form.
2) Evaluate the definite integral from 3 to √18: ∫(√9√(x(squared)−9)/x dx
3) Compute the given integral. ∫√(x(squared)-9)
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