Question

Evaluate the geometric series described. -1 - 4 - 16 - 64..., n = 7

Evaluate the geometric series described.

-1 - 4 - 16 - 64..., n = 7

Homework Answers

Answer #1

Given

A GP series ----> - 1 - 4 - 16 - 64 ......... + nth

n ----> number of terms

r ---> Common ratio = 2nd term / 1st term = - 4 / ( - 1 ) = 4

Sn = a*( r^n - 1 ) / ( r - 1 )

Sn = ( - 1 )*( 4^n - 1 ) / ( 4 - 1 )

here , n = 7

Sn = ( - 1 )*( 4^7 - 1 ) / ( 4 - 1 )

Sn = - 5461

Sum of the series ---> - 5461

nth = a*r^( n - 1 )

nth is the last term

nth = ( - 1 )*4^( 7 - 1 )

nth = ( - 1 )*4^6

nth = - 4096  

So, the GP series is - 1 - 4 - 16 - 64 ......... - 4096

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. Consider the geometric series −1/4+3/16−9/64+27/256+... Use summation notation to write this series and determine whether...
1. Consider the geometric series −1/4+3/16−9/64+27/256+... Use summation notation to write this series and determine whether it converges. If it does, find the sum.
1. Write a geometric series with a starting index of n = 0 which has a...
1. Write a geometric series with a starting index of n = 0 which has a sum of 4. Show how you come up with your series. 2. Using the geometric series you wrote in 1, show how you would find the sum if the starting index was n = 3. 3. Write a geometric series that diverges.
Evaluate the following sum 1+1/4-1/16-1/64+1/256+1/1024--++ ...
Evaluate the following sum 1+1/4-1/16-1/64+1/256+1/1024--++ ...
find the sum of the following series:[(-1)^n pi^2n+1]/4(16)^n (2n+1)
find the sum of the following series:[(-1)^n pi^2n+1]/4(16)^n (2n+1)
Which of the following statements is true? a) The geometric series Σ∞n=1 r^n is always convergent....
Which of the following statements is true? a) The geometric series Σ∞n=1 r^n is always convergent. b) for the series Σ∞n=1an, if lim n→∞ an = 1/3, then the series will be convergent. c) If an> bn for all values of n and Σ∞n=1 bn is convergent, then Σ∞ n=1an is also convergent. d) None of the above
Mark each series as convergent or divergent 1. ∑n=1∞ln(n)4n 2.  ∑n=1∞ 4+8^n/2+3^n 3. ∑n=1∞ 6n/(n+3) 4. ∑n=1∞1/(7+n2−−√6)...
Mark each series as convergent or divergent 1. ∑n=1∞ln(n)4n 2.  ∑n=1∞ 4+8^n/2+3^n 3. ∑n=1∞ 6n/(n+3) 4. ∑n=1∞1/(7+n2−−√6) 5.  ∑n=3∞ 6/(n^4−16)
Given the alternating series:    n=2∞(-1)^n/ln(n) (7 pts) Determine if the series converge absolutely.    (Use the fact...
Given the alternating series:    n=2∞(-1)^n/ln(n) (7 pts) Determine if the series converge absolutely.    (Use the fact that: ln n < n ) (7 pts) Determine if the series converge conditionally. (7 pts) Estimate the sum of the infinite series using the first 4 terms in the series and estimate the error. (7 pts) How many terms should we use to approximate the sum of the infinite series in question, if we want the error to be less than 0.5?
For the series ∑∞ n=0 ((-1)^(n-1)) ((x-7)^n)/n a) Find the radius and interval of absolute convergence....
For the series ∑∞ n=0 ((-1)^(n-1)) ((x-7)^n)/n a) Find the radius and interval of absolute convergence. b) For what values of x does the series converge conditionally?
rewrite the geometric series 1/8+2/80+4/800+8/8000+.....with summation notation and determine if it converges or diverges if the...
rewrite the geometric series 1/8+2/80+4/800+8/8000+.....with summation notation and determine if it converges or diverges if the series converge find the value that it converges to.
Infinity Sigma n=1 (n+1 / n^7/3 + sqrt n) Does this series converge or diverge?
Infinity Sigma n=1 (n+1 / n^7/3 + sqrt n) Does this series converge or diverge?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT