Question

Solve the differential equation by variation of parameters. y'' + 3y' + 2y = 1/(4+e^x)

Answer #1

Solve the differential equation by variation of parameters.
y'' + 3y' + 2y = 1 / (7 + e^x)

Solve the differential equation by using variation of parameter
method
y^''+3y^'+2y = 1/(1+e^2x)

Solve the second-order linear differential equation
y′′ − 2y′ − 3y = −32e−x using the method of variation of
parameters.

differential equations!
find the Differential Equation General Solve by using
variation of parameters method...
y''' - 3y'' +3y' - y =12e^x

Solve Differential equation by variation of parameters method.
y"-5y'+6y=e^x

solve the given differential equation by variation of
parameters.
y”+y=1/cos(x)

Find a particular solution for the differential equation by
variation of parameters.
y''- y' -2y = e^3x , y(0) = -3/4 , y'(0)=15/4

use the method of undetermined coefficients to solve the
differential equation)
y'' + 2y' - 3y = (x2 + x + 1) + e-3x

use variation of parameters to determine a particular solution
to the given equation y'''-3y''+3y'-y=e^x

Solve the following differential equations by using variation of
parameters.
y''-y'-2y=e3x

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