Question

Find the area of the indicated region.

between y=2x^2+6x-3 and y=-x^2+3x+3 for x in [-2,2]

Answer #1

we have

the intersection point is,

we have to find the area between a curve f(x) and g(x) on an interval [a, b] given by,

put f(x) = 2x^{2} + 6x - 3, g(x) = -x^{2} + 3x +
3, a = -2 and b = 2,

find the area of the region bounded by the graph of
y=x^3-2x^2-x+2 and y=3x^2-5x+2

Find the area of the indicated region.
Between y=x and y=x^3 for x in [-1,1]

Find the area of the region bounded by the graphs of the given
equations.
y=2x^2-9x+13, y=x^2+3x-7

find the area of
y=x^2 -6x +8
y= 2x-7

Find all the real roots of 6x^5 -x^4 + 2x^3 -3x^2 + 2x -18

1.Find the area of the region between the curves y= x(1-x) and y
=2 from x=0 and x=1.
2.Find the area of the region enclosed by the curves
y=x2 - 6 and y=3 between their
interaction.
3.Find the area of the region bounded by the curves
y=x3 and y=x2 between their interaction.
4. Find the area of the region bounded by y= 3/x2 ,
y= 3/8x, and y=3x, for x greater than or equals≥0.

Find the area of the region enclosed by the curves
y=x2+2x, y=x2-6x+8 and the line y= -1.

Find the area of the indicated region. We suggest you graph the
curves to check whether one is above the other or whether they
cross, and that you use technology to check your answer. Between y
= 2x2 + 6x − 2 and y = −x2 + 3x + 4 for x in [−2, 2]

Find the area of the indicated region. We suggest you graph the
curves to check whether one is above the other or whether they
cross, and that you use technology to check your answer.
Between y = 2x2 +
6x − 2 and y =
−x2 + 3x + 4 for
x in [−2, 2]

Calculate the area of the surface bounded by y = x^3 and y =
−2x^2 + 3x
(area between curves)

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