Find the area of the indicated region.
between y=2x^2+6x-3 and y=-x^2+3x+3 for x in [-2,2]
we have
the intersection point is,
we have to find the area between a curve f(x) and g(x) on an interval [a, b] given by,
put f(x) = 2x2 + 6x - 3, g(x) = -x2 + 3x + 3, a = -2 and b = 2,
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