Question

Write an equation in slope-intercept form a line that is perpendicular to y = 3x-4 and that contains (-12, 2).

a. y = -1/3 + 2
b. y = -1/3 - 2
c. y = 3x + 26
d. y = 3x + 24

Answer 1

SOLUTION:: option (b)

THE equation is y=3x-4

the slope of this equation is m1=3

and the through point (-12,2)

lets the perpendicular equation slope is m2

we know that (m1)(m2)= -1

(3)(m2)= -1

  

now we can write the equation of perpendicular is y=m2x+b which is pass through the point    (-12,2)

so

y=m2x+b

  

he equation of perpendicular is y=m2x+b

ANSWER: Option (b ) is correct answer