Write an equation in slope-intercept form a line that is perpendicular to y = 3x-4 and that contains (-12, 2).
a. y = -1/3 + 2
b. y = -1/3 - 2
c. y = 3x + 26
d. y = 3x + 24
SOLUTION:: option (b)
THE equation is y=3x-4
the slope of this equation is m1=3
and the through point (-12,2)
lets the perpendicular equation slope is m2
we know that (m1)(m2)= -1
now we can write the equation of perpendicular is y=m2x+b which is pass through the point (-12,2)
he equation of perpendicular is y=m2x+b
ANSWER: Option (b ) is correct answer
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