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How much of a peanut/cashew mixture consisting of 60% peanuts must be mixed with a peanut/cashew...

How much of a peanut/cashew mixture consisting of 60% peanuts must be mixed with a peanut/cashew mixture consisting of 35% peanuts to obtain 50 pounds of a peanut/cashew mixture consisting of 50% peanuts?

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Answer #1

Let the number of pounds of  peanut/cashew mixture consisting of 60% peanuts = x

Then the number of peanut/cashew mixture consisting of 35% peanuts = 50 - x

Then

0.6x + 0.35 (50-x) = 0.5 (50)

0.6x + 17.5 -0.35x = 25

0.25x + 17.5 = 25

0.25x = 7.5

x = 7.5/0.25 = 30

So,

the number of pounds of  peanut/cashew mixture consisting of 60% peanuts = x = 30 pounds

Then the number of peanut/cashew mixture consisting of 35% peanuts = 50 - x = 50 - 30 = 20 pounds

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