If in triangle ABC and Triangle XYZ we have AB = XY, AC = XZ, but m<A > m<X, then BC > YZ. Conversely, if BC > YZ then m<A > m<X.
Given : and are triangles. AB = XY , AC = XZ, but
Prove that :
Proof :
In and ,
....... (given)...... 1.
........ (given)...... 2.
Suppose If IT WAS GIVEN
Then ................... (By Congruence rule: If two sides and its including angle are congruent to the corresponding two sides and including angle of another triangle, then both the sides are congruent by S-A-S test)
.................. (Corresponding sides of congruent triangles)
But GIVEN is :
......... (Theorem : Side opposite to Greater angle is Greater....)....(3)
Conversely,
If GIVEN IS :
then ........... (Converse of above (3) : Angle opposite to Greater side is Greater......)
Get Answers For Free
Most questions answered within 1 hours.