Find an equation for the line with the given properties. Express the equation in general form. Slope 9/4 ?; containing the point (-6,-8)
Answer: 9x-4y=-22
Explaination:
The equation of line with slope (m) and passing through the point (x1, y1) is given by the formula.
y-y1=m(x-x1) ----------------------------------------- (1)
Here, m=(9/4) and (x1, y1)=(-6, -8). So, using eqn 1
y-(-8)=(9/4){x-(-6)}
y+8=(9/4){x+6}
multiplying both sides by 4
4*(y+8)=4*(9/4){x+6}
4y+32=9{x+6}
4y+32=9x+54
OR
9x+54=4y+32
subtracing 4y and 54 from both sides
9x+54-4y-54=4y+32-4y-54
9x-4y=-22
This is the required equation of line in the general form (ax+by=c).
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