Question

Find the absolute maximum and absolute minimum of the function

f(x) = x 3 − 6x 2 + 5

on interval [3, 6]

This problem is from chapter 4 of calculus early transcendentals

Answer #1

Find the absolute maximum and minimum values of f (x) = x^3 −
6x^2 + 9x + 1 on [1, 6]

Let f(x)=4x(^3)-9x(^2)+6x-1 Find:
a.) absolute minimum of f(x) on the interval [0,1].
b.) absolute maximum of f(x) on the interval [0,1].

Consider the function f(x)=6x^2−4x+11, on the interval
, 0≤x≤10.
The absolute maximum of f(x) on the given interval is at x =
The absolute minimum of f(x) on the given interval is at x =

Find the maximum and minimum of the function f (x, y) = 6x − 2y
subject to the constraint . 3x^2 + y ^2 = 4

Find the absolute maximum and the absolute minimum values of
f(x) = 4 x^3-13 x^2+10 x+6 over the interval [0,2]. You must
include a hand-drawn graph of the situation showing important
points and explain in words how you know your answer is correct.
Your explanation should make sense to a calculus student who has
not seen the material

Find the absolute maximum and absolute minimum values of
f on the given interval.
f(x) = 4x3 −
12x2 − 36x +
6,
[−2, 4]

find ALL absolute maximum and absolute minimum values
for the function f(x)= 2sinx + 2cosx over the interval [0,pi/3]

Find the absolute maximum and absolute minimum values of f on
the given interval: x^4-8x^2+8 [-3, 4]
Absolute minimum:
Absolute maximum:

Find the absolute maximum value and the absolute minimum value
of the function f ( x , y ) = x 2 y 2 + 3 y on the set D defined as
the closed triangular region with vertices ( 0 , 0 ), ( 1 , 0 ),
and ( 1 , 1 ), that is, the set D = { ( x , y ) | 0 ≤ x ≤ 1 , 0 ≤ y
≤ x }...

Let f(x) = x 1/2 (3−x). Find the absolute maximum and absolute
minimum values of the f(x) on the interval [1, 3].

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