Question

Find the maximum value and the absolute minimum value of the
function f(x)=x^2-(1/x) on the interval [-2.25,-0.25]

Answer #1

Find the absolute maximum value and the absolute minimum value
of the function f ( x , y ) = x 2 y 2 + 3 y on the set D defined as
the closed triangular region with vertices ( 0 , 0 ), ( 1 , 0 ),
and ( 1 , 1 ), that is, the set D = { ( x , y ) | 0 ≤ x ≤ 1 , 0 ≤ y
≤ x }...

Find the absolute maximum and absolute minimum values of f on
the given interval. f(x)= ln(x^2+x+1), [-1,1]

Find the absolute maximum and absolute minimum values of f on
the given interval. f(x) = 3x^2 − 18x + 8, [0, 8] absolute minimum
value.

Find the absolute minimum and maximum of the function
on the given closed interval.
f(x)=3x4
-4x3-12x2+1 on [-2, 3]

find the absolute maximum and absolute minimum values of f on the
given interval
f(x) = x^4-2x^2+1 [-2,3]

Find the absolute maximum and absolute minimum values of f on
the given interval. f(x) = x4 − 2x2 + 1, [−2, 3] absolute minimum
Incorrect: Your answer is incorrect. absolute maximum Incorrect:
Your answer is incorrect.

Find the absolute maximum value and the absolute minimum value
of the function f(x,y)=(1+x2)(1−y2) on the disk
D={(x,y) | x2+y2⩽1}

Find the absolute maximum and absolute minimum of the
function
f(x) = x 3 − 6x 2 + 5
on interval [3, 6]
This problem is from chapter 4 of calculus early
transcendentals

Find the absolute maximum and absolute minimum values of f on
the given interval.
f(x) = xe-x^2/128, [-3,16]

find the absolute maximum and absolute minimum values of f on
the given closed interval
f(x)=5-x^2
[-3,1]

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