Question

Find the general solution of the given differential equation.

y'' − y' − 2y = −8t + 6t^{2}

y(t) =

Answer #1

a) Find the general solution of the differential equation
y''-2y'+y=0
b) Use the method of variation of parameters to find the general
solution of the differential equation y''-2y'+y=2e^t/t^3

Find the general solution to the differential equation
2y'+y=3x

find the general solution of the differential equation:
y''+2y'+4y=xcos3x

ﬁnd the general solution of the given differential equation
1. y''−2y'+2y=0
2. y''+6y'+13y=0
ﬁnd the solution of the given initial value problem
1. y''+4y=0, y(0) =0, y'(0) =1
2. y''−2y'+5y=0, y(π/2) =0, y'(π/2) =2
use the method of reduction of order to ﬁnd a second solution of
the given differential equation.
1. t^2 y''+3ty'+y=0, t > 0; y1(t) =t^−1

find the general solution of the differential equation: y' + 2y
= te^−4t. Use lower case c for the constant in your answer.
y(t) = _________________

Find the general solution to the differential equation
t^2y'' - 2ty' + 2y = 4

Find the general solution of the differential equation
y′′ − 2y′ − 3y = ae3t, where a is a constant

Find the general solution of the given differential
equation.
y'' + 12y' + 85y = 0
y(t) =

Oridinary Differential equations:
given that y=sinx is a solution of
y(4)+2y'''+11y''+2y'+10y=0,
find the general solution of the DE.

Find the general solution of the differential equation: y' + 2y
= 2sin (4t) Use lower case c for the constant in your answer.

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