According to Hooke’s Law, the force required to maintain a spring stretched x units beyond its natural length is proportional to x, that is,fx=k x. A force of 40 N is required to hold a spring that has been stretched from its natural length of 10 cm to a length of 15 cm. How much work is done in stretching the spring from 15 cm to 18 cm?
Item 3a Below, show all work to set up the integral that
represents the work done in stretching the spring from 15 cm to 18
cm. Circle the integral that represents this work.
Item 3b Evaluate the integral that represent the work done in stretching the spring from 15 cm to 18 cm. Make sure to include units.
Get Answers For Free
Most questions answered within 1 hours.