The position s of a point (in feet) is given as a function of time t (in seconds). HINT [See Example 1.] s = √ t + 6t2; t = 9 (a) Find the point's acceleration as a function of t. s''(t) = ft/sec2 (b) Find the point's acceleration at the specified time. s''(9) = ft/sec2
Get Answers For Free
Most questions answered within 1 hours.