Question

Let the function f and g be defined as f(x) = x/ x − 1 and...

Let the function f and g be defined as f(x) = x/ x − 1 and g(x) = 2 /x +1 . Compute the sum (f + g)(x) and the quotient (f/g)(x) in simplest form and describe their domains.

(f + g )(x) =

Domain of (f+g)(x):

(f/g)(x) =

Domain of (f/g)(x):

Homework Answers

Answer #1

Given f(x) = x / (x-1) and g(x) = 2 / (x+1)

Then f+g(x) = f(x) + g(x)

Thus, f+g(x) = [ x/(x-1) ] + [ 2/(x+1) ]

f+g(x) = [ x(x+1) + 2(x-1) ] / (x-1)(x+1)

f+g(x) = [ x2 + x +2x - 1 ] / (x2 - 12)

f+g(x) = ( x2 +3x -1 ) / (x2 -1)

Hence, f+g(x) = [ x2 +3x -1 ] / [ x2 -1 ]

f+g(x) is not defined when the denominator is zero

Thus, (x+1)(x-1) ≠ 0 implies x ≠ 1 , -1

Domain of f+g(x) is  (- , -1 ) U ( -1 , 1 ) U ( 1 , )

f/g (x) = f(x) / g(x)

Thus, f/g(x) = [ x / (x-1) ] / [2 / (x+1) ]

= [ x / (x-1) ] × [ (x+1) / 2 ]

= x(x+1) / 2(x-1)

= ( x2 + x ) / (2x -2)

Hence f/g (x) = [ x2 +x ] / [ 2x -2 ]

f/g (x) is not defined when the denominator is zero

Thus, 2x-2 ≠ 0

Thus, 2x ≠ 2 implies x ≠1

Domain is ( - , 1 ) U ( 1 , )

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