Question

I need to evaluate the double integral:I from 0 to 3, I from 0 to sqrt(9-y^2),...

I need to evaluate the double integral:I from 0 to 3, I from 0 to sqrt(9-y^2), integrand is Sqrt(1+x^2 + y^2)dxdy. I know I need to convert to polar coordinates: x = rcos theta, y = rsin- theta. The integrand becomes sqrt(1+r^2)?????. I know how to integrate that, but I don’t know how to convert the bounds for the integrals. I think for dtheta, because we go from the x-axis to the y-axis, so we go from 0 to pi/2. Is that the correct reasoning? But how do I calculate the bounds for the integral over r?

Math   Calculus   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Evaluate the following double integral by first converting to polar coordinates: SS(e^(x^2+y^2)dydx 0 ≤ x ≤...
Evaluate the following double integral by first converting to polar coordinates: SS(e^(x^2+y^2)dydx 0 ≤ x ≤ 2, -(sqrt(4-x^2)) ≤ t ≤ sqrt(4-x^2)
Evaluate the following double integral by first converting to polar coordinates: S(2,0)S(sqrt(4-x^2),-sqrt(4-x^2))e^(x^2+y^2)dydx
Evaluate the following double integral by first converting to polar coordinates: S(2,0)S(sqrt(4-x^2),-sqrt(4-x^2))e^(x^2+y^2)dydx
The integral ∫-1(bottom) to 0 ∫sqrt(−1−x2)(bottom) to 0 −4/(−5+sqrt(x^2+y^2)dydx is very hard to do. If you...
The integral ∫-1(bottom) to 0 ∫sqrt(−1−x2)(bottom) to 0 −4/(−5+sqrt(x^2+y^2)dydx is very hard to do. If you put it in polar form it's much easier, ∫ba∫dc f(r,θ)r drdθ it's much easier, but you need to work out the new limits. Find a,b,c,d and the value of the integral. a= b= c= d= ∫-1(bottom) to 0∫-sqrt(1−x^2)(bottom) to 0 a/(b+sqrt(x^2+y^2)dydx=
Evaluate the integral using trig substitution. definite integral from 1 to sqrt(2) 6 / (x^2 sqrt(4-x^2))dx...
Evaluate the integral using trig substitution. definite integral from 1 to sqrt(2) 6 / (x^2 sqrt(4-x^2))dx (a) write the definition for x using the triangle (b) write the new integral before any simplification (c) write the new integral after simplifying and in the form ready to integrate (d) write the solution in simplified exact form write all answers next to the specified letter above
Find the integral that represents: The volume of the solid under the cone z = sqrt(x^2...
Find the integral that represents: The volume of the solid under the cone z = sqrt(x^2 + y^2) and over the ring 4 ≤ x^2 + y^2 ≤ 25 The volume of the solid under the plane 6x + 4y + z = 12 and on the disk with boundary x2 + y2 = y. The area of ​​the smallest region, enclosed by the spiral rθ = 1, the circles r = 1 and r = 3 & the polar...
using the change of variable x =u/v, y=v evaluate "double integral(x^2+2y^2)dxdy: R is the region in...
using the change of variable x =u/v, y=v evaluate "double integral(x^2+2y^2)dxdy: R is the region in the first quadrant bounded by the graphs of xy=1, xy=2, y=x, y=2x
The curve x = sqrt( (2y-y ^ 2) ) with 0 <= y <= 1/2 is...
The curve x = sqrt( (2y-y ^ 2) ) with 0 <= y <= 1/2 is rotated on the y axis. Find the surface area of the solid obtained.
Consider the sum of double integrals Z1 1/√2Zx √1−x2 xy dy dx +Z√2 1 Zx 0...
Consider the sum of double integrals Z1 1/√2Zx √1−x2 xy dy dx +Z√2 1 Zx 0 xy dy dx +Z2 √2Z√4−x2 0 xy dy dx . a. [4] Combine into one integral and describe the domain of integration in terms of polar coordinates. Give the range for the radius r. b. [4] Compute the integral.
Evaluate double integral Z 2 0 Z 1 y/2 cos(x^2 )dx dy (integral from 0 to...
Evaluate double integral Z 2 0 Z 1 y/2 cos(x^2 )dx dy (integral from 0 to 2)(integral from y/2 to 1) for cos(x^2) dx dy
Quesiton: Compute the surface integral of f(x,y,z)=x^2 over z=sqrt(x^2+y^2), 0<=z<=1.
Quesiton: Compute the surface integral of f(x,y,z)=x^2 over z=sqrt(x^2+y^2), 0<=z<=1.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT