Question

Let f(x) = x 1/2 (3−x). Find the absolute maximum and absolute minimum values of the f(x) on the interval [1, 3].

Answer #1

Let f(x)=4x(^3)-9x(^2)+6x-1 Find:
a.) absolute minimum of f(x) on the interval [0,1].
b.) absolute maximum of f(x) on the interval [0,1].

Find the absolute maximum and absolute minimum values of f on
the given interval. f(x) = x4 − 2x2 + 1, [−2, 3] absolute minimum
Incorrect: Your answer is incorrect. absolute maximum Incorrect:
Your answer is incorrect.

Find the absolute maximum and absolute minimum values of f on
the given interval. f(x)= ln(x^2+x+1), [-1,1]

Find the absolute maximum and absolute minimum values of f on
the given interval: x^4-8x^2+8 [-3, 4]
Absolute minimum:
Absolute maximum:

find the absolute maximum and minimum values of the function
f(x) = 10x / 1+64x^2 on the interval [-1/24, 2]
Absolute maximum value =
Absolute minimum value =

find the absolute maximum and absolute minimum values of f on the
given interval
f(x) = x^4-2x^2+1 [-2,3]

Find the absolute maximum and absolute minimum values of f on
the given interval.
f(x) = xe-x^2/128, [-3,16]

Find the absolute maximum and absolute minimum values of f on
the given interval. f(x) = 3x^2 − 18x + 8, [0, 8] absolute minimum
value.

Find the absolute maximum and minimum values of f (x) = x^3 −
6x^2 + 9x + 1 on [1, 6]

find the absolute maximum and absolute minimum values of f on
the given closed interval
f(x)=5-x^2
[-3,1]

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