For each of the following systems of linear equations, use Gauss-Jordan elim-
ination to find the set of solutions. Write the set of solutions in vector form.
Assume in each case that the set of variables has the form x 1 , . . . , x n (so, for instance, x 1 is a variable even if it does appear in any of the equations).
4. x2 + 2x3 -x5 = 6
The only equation given is x2+2x3-x5 = 6.
Then, we have x2 = 6-2x3+x5 so that (x1,x2,x3,x4,x5) = (x1, 6-2x3+x5 ,x3,x4,x5) = (0,6,0,0,0)+ x1(1,0,0,0,0) + x3(0,-2,1,0,0)+x4(0,0,0,1,0) +x5(0,1,0,0,1). Now, let x1 = r, x3 = s, x4 = t and x5 = u. Then, the vector form of the general solution is (x1,x2,x3,x4,x5) = (0,6,0,0,0)+ r(1,0,0,0,0) + s(0,-2,1,0,0) +t(0,0,0,1,0) +u(0,1,0,0,1) where r, s, t, u are arbitrary real numbers.
Note:
The Gauss-Jordan elimination can be used where there are more than 1 linear equations.
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