Question

Chemical Mixtures

Two chemicals react to form another chemical. Suppose the amount of the chemical formed in time t (in hours) is given by

x(t) = (14(1-(3/4)^4t))/(1-(1/4)(3/4)^4t)

How many pounds of the chemical are formed eventually? (Hint: You need to evaluate the limit of x(t) as t → ∞.)where x(t) is measured in pounds.

lbs

Answer 1

x (+) = ? 484 (+4)*then 47 14 Z in hours (t) in pounds Zoo 24 → If we put " t = s in the above equation then our answer will be us So using "L-kospital" rule C.g. - x (t) = axtb d lox+b) da cxto (x²+d) ato Ito 2xc so opplying this, & + 2 47 selt) 141-)*) 0 + 14 (+0)) 7 **** * Hikartat) co +6°)= n2m 2-1 YE) 14x48_)** - (+) (2 - 56 2) = 156 pounds/