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Let Q1 be a constant so that Q1 = L(−3, 2), where z = L(x, y)...

Let Q1 be a constant so that Q1 = L(−3, 2), where z = L(x, y) is the equation of the tangent plane to the surface z = ln(5x − 7y) at the point (x0, y0) = (2, 1). Let Q = ln(3 + |Q1|). Then T = 5 sin2 (100Q)

satisfies:— (A) 0 ≤ T < 1. — (B) 1 ≤ T < 2. — (C) 2 ≤ T < 3. — (D) 3 ≤ T < 4. — (E) 4 ≤ T ≤ 5.

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