Question

A pot of soup is removed from a burner on a stovetop. Its initial temperature is...

A pot of soup is removed from a burner on a stovetop. Its initial temperature is 206 degrees. After exactly

11 ​minutes, it has cooled to 169 degrees. Assuming that the room temperature is 73 ​degrees, find the temperature of the soup exactly 23 minutes after it is removed from the burner.  ROUND TO THE NEAREST DEGREE.

The​ soup's temperature after 23 minutes is

A. 140 degrees

B. 122 degrees

C.129 degrees

D.148 degrees

E. None of the above

Math   Calculus   
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Homework Answers

Answer #1

Note: to find the value of temperature after 23 minutes we use Newton's law of cooling: that is

T= Ts+(T0- Ts)e^-(kt).

Details explained in the image.

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