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Air is being pumped into a spherical balloon so that its volume increases at a rate...

Air is being pumped into a spherical balloon so that its volume increases at a rate of 30cm3/s. How fast is the surface area of the balloon increasing when its radius is 12cm? Recall that a ball of radius r has volume V=43πr^3 and surface area S=4πR^2

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Answer: 5 cm^2/s

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