Question

Find the exact area of the surface obtained by rotating the
curve about the *x*-axis.

A. y = sqrt(1+e^{x} ) , 0 ≤ x ≤ 3

B. x = 1/3(y^{2}+2)^{3/2 ,} 4 ≤ x ≤ 5

Answer #1

Find the exact area of the surface obtained by rotating the
curve about the x -axis.
y = sin π x/ 5 , 0 ≤ x ≤ 5

Find the exact area of the surface obtained by rotating the
curve about the x axis.
1. Original problem y= x^3 from 0 < x < 2
I got up to the SA= 2 pi the integral of 1 to 145 of (x^3)(the
square root of (1+9x^4))dx
I don't know how to integrate from this part on to get the exact
answer.

Find the area of the surface obtained by rotating the following
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Find the area of the surface obtained by rotating the curve y =
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?=5?^2y
from ?=0 to ?=8 about the y-axis.

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y = 5x4, y = 5x, x ≥
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y = 3 cos(πx), y = 12x2 −
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Find the volume V of the solid obtained by rotating the
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2x = y2, x = 0, y =
5; about the...

Use Simpson's Rule with n = 10 to approximate the area
of the surface obtained by rotating the curve about the
x-axis. Compare your answer with the value of the integral
produced by your calculator. (Round your answer to six decimal
places.)
y = x +sqrt x, 2 ≤ x ≤ 5

The
curve x = sqrt( (2y-y ^ 2) ) with 0 <= y <= 1/2 is rotated on
the y axis. Find the surface area of the solid obtained.

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