Question

Find the area of the region bounded by the curves y=3x2 and y=−8x+3. please show work. thanks

Answer #1

1) Find the area of the region bounded by the curves y = 2x^2 −
8x + 12 and y = −2x + 12
a) Find the volume when the area in question 1 is revolved
around the x-axis.
b)Find the volume when the area in question 1 revolved around
the y-axis.

1.Find the area of the region between the curves y= x(1-x) and y
=2 from x=0 and x=1.
2.Find the area of the region enclosed by the curves
y=x2 - 6 and y=3 between their
interaction.
3.Find the area of the region bounded by the curves
y=x3 and y=x2 between their interaction.
4. Find the area of the region bounded by y= 3/x2 ,
y= 3/8x, and y=3x, for x greater than or equals≥0.

please show the work for computing the area of the region bounded
by the curve provided
y=1
y=x^2-11.2

Find the area of the region bounded by the curves x+y^2= 2 and
x+y=0

Calculate the area of the region bounded by the curves x=3-y^2 and
x=y+1

Find the centroid of the region bounded the following curves.
Show a graph of the region.
1. ? = ? ^? , ? = ? ^−? , ? = 0, and ? = ??2.
2. ? = −? ^2 + 4? − 3 and the y-axis

1- Find the area enclosed by the given curves.
Find the area of the region in the first quadrant bounded on the
left by the y-axis, below by the line above left
by y = x + 4, and above right by y = - x 2 + 10.
2- Find the area enclosed by the given curves.
Find the area of the "triangular" region in the first quadrant that
is bounded above by the curve , below by the curve y...

Sketch the region bounded by the given curves. y = 3 sin x, y =
ex, x = 0, x = π/2 Find the area of the region.

Find the area of the region bounded by the above curves:
y=1/(x+2), y=(x+2)^2, x=-3/2, x=2

Find the area of the region bounded by the parabola y = 1 + 2x -
x^2 and the parabola y = 1 + x^2. Please show the steps involved to
obtain the boundaries.
Please be legible and do not use cursive. Please show all work,
including ALL algebra. Thank you for your help!

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