use the method of variation of parameters to determine the general solution of the given differential equation.
y(4)+2y''+y=sin t
answer: c1cos(t)+c2sin(t)+c3t*cos(t)+c4t*sin(t)-1/8t2sin(t)
I can't get past finding the Wronskian, not to mention w1,w2,w3, and w4. The matrix seems way to complicated when I cross multiply using the determinant method. Is there an easier way?
Now if you have any doubt then leave a comment I'll try to resolve it.
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