Question

1. For jumps that exceed 13 sec, the polynomial 173t − 369 can be used to approximate the distance, in feet, that a skydiver has fallen in t seconds. Approximately how far has a skydiver fallen 20 sec after having jumped from a plane?

2. Identify the degree of each term of polynomial.

xy3 + 7x3y^2 − 6xy4 + 2

PLEASE ANSWER BOTH WITH STEP BY STEP INSTRUCTIONS ON HOW TO SOLVE! Thanks.

Answer 1

1) Given the polynomial

173t-369

Given t =20 sec

= 173(20)-369

=3091 ft

2) Given the polynomial

xy^3+7x^3y^2-6xy^4+2

In this polynomial four terms are there

In the first term degree is 4

(since x power is 1 and y power is 3 so total is 4)

In the second term degree is 5

(Since x power is 3 and y power is 2 so total is 5)

In the third term degree is 5

(Since x power is 1 and y power is 4 so total is 5)

In the fourth term degree is 0

(Since there is no x and y terms)