Question

Jacobs & Johnson, an accounting firm, employs 15 accountants, of whom 6 are CPAs. If a delegation of 4 accountants is randomly selected from the firm to attend a conference, what is the probability that 4 CPAs will be selected? (Round your answer to three decimal places.)

Answer 1

Total No. of employs = 15

Total No. of CPA's = 6

Total no. of non CPA's = 15-6= 9

Probability of selecting 4 CPA's= Total No. of ways of selecting 4 CPA's out of 6 CPA's/Total No. of ways of selecting 4 employees out of 15 employees .....-eq i>

Total No. of ways of selecting 4 CPA's out of 6 CPA's =6C4 = 6! / 4! * 2! = 720 / 24*2 = 15

Total No. of ways of selecting 4 employees out of 15 employees = 15C4 = 15! / 4! * 11!= 15*14*13*12/4*3*2*1 = 1365

Putting these values in eq i> we get

Probability of selecting 4 CPA's=15/1365 = 0.0109 or 0.011