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Show the rectangular box with fixed volume V=27 and smallest possible surface area is a cube....

Show the rectangular box with fixed volume V=27 and smallest possible surface area is a cube. Hint: if the sides are x, y, and z, then V=xyz and surface area is given by S=2xy+2yz+2xz. Use the constraint in volume to turn the problem into one of two variables.

Math   Calculus   
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