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x3+x2-36x=36 Solve

x3+x2-36x=36

Solve

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Answer #1

Given equation, x3+x2-36x=36

Given equation by trial and error, we can say x = -1 is one solution.

From this point, we can find the other two roots by using the Horner's rule for calculating the other two roots.

writing all the co-efficients of given equation, x3+x2-36x-36 = 0.

and in row2, at x =-1

1 1 -36 -36
0 -1 0 36
1 0 -36 0

From above table, the final equation in quadratic that we can obtain is,

x2-36 = 0

implies,

x = 6 or x = -6

The three roots are, x = -1, 6, -6

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