Please show complete, step by step working.
i) cos x = -√3/2
ii) 2 sin 2x = 1
iii) cot x = 1/√3
b) Solve the following for 0° ≤ q ≤ 360°,
i) sin^2Q = 3/4
ii) 2 sin^2Q - sinQ = 0 {Hint: factor out sinθ)
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