Find the fifth term of the geometric sequence 6?, 2?, 2/3...
Given geometric series: 6, 2, 2/3..........
We know the geometric series will be of the form: a, ar, ar2, ar3, ar4, ar5..........
So, comparing both and we have
First term, a = 6,
Common ratio, r = ar/a = 2/6 = 1/3
So, we have to find the fifth term of the geometric sequence: a, ar, ar2, ar3, ar4, ar5..........
fifth term is = ar4
substituting the values of a and r, we get
6(1/3)4 = 6/81 = 2/27
Fifth term of the series is 2/27
The series looks like: 6?, 2?, 2/3, 2/9, 2/27, 2/81.........
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