Question

Find the equation of the tangent line to the graph of y = e x 2−1 at the point (1, 1)

Answer #1

1. Find the equation of the tangent line to the graph of ?2? −
5??2 + 6 = 0 at (3,1).
2.. Find the equation of the normal line to the graph of sin(??) =
? at the point (?/2 ,1).
3.. Find the equation of the tangent line to the graph of cos(??) =
? at the point (0.1)
Find implicit differentiation of dy/dx
a) xy=x+y
b) xcosy=y
c)x^3 +y^2=0

test question
find an equation of the line / tangent to the graph of the
equation
x^2+y^2=3y at the point (-squareroot 2,2)

a) Find the equation of the tangent line to f(x) = e –x at the
point (1, e –1).
b) Find the equation of the tangent line to f(x) = 3x2 – 2x + 5 at
x = 2.

Find an equation for the line tangent to the graph of
f(x)=sqrt(x)/6x−1 at the point (2,f(2)).

f(x)=1/2x ln x^4, (-1,0)
a) find an equation of the tangent line to the graph of the
function at the indicated point.
b) Use a graphing utility to graph the function and its tangent
line at the point.

Find an equation for the line tangent to the x^(3)+y^(3)= 9−x at
the point (2,−1).

Find an equation for the line tangent to the following curve at
the point (4,1).
1−y=sin(x+y^(2)−5)
Use symbolic notation and fractions where needed. Express the
equation of the tangent line in terms of y
and x.
equation:

Find the equation of the tangent line to the graph of the
function f(x)=(x^2+8)(x−2) at the point (1,−9).
I thought it was re-writen as (2x^2 + 8)(x-2) then plugging in 1
for x and solving. I came up withit in slope form y = -20x - 1 but
says im wrong. What steps did i miss?

1.) Find the equation of the tangent line to the graph of the
function f(x)=5x-4/2x+2 at the point where x=2
2.) Find the derivative: r(t)=(ln(t^3+1))^2

Write the equation of the tangent line to the graph of y = (x^2
− 16x)/(4x − x^3) at x = 4. Check the reasonableness of your answer
by graphing both the function and the tangent line

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