Question

f(x)=(-6x^2+2)^8(-9x^2-2)^13 find f’(x)

f(x)=(-6x^2+2)^8(-9x^2-2)^13 find f’(x)
Math   Calculus   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find the absolute maximum and minimum values of f (x) = x^3 − 6x^2 + 9x...
Find the absolute maximum and minimum values of f (x) = x^3 − 6x^2 + 9x + 1 on [1, 6]
Find only the rational zeros of the following function: f(x)=x^4+6x^3-9x^2-12x+14
Find only the rational zeros of the following function: f(x)=x^4+6x^3-9x^2-12x+14
Let f(x)=4x(^3)-9x(^2)+6x-1 Find: a.) absolute minimum of f(x) on the interval [0,1]. b.) absolute maximum of...
Let f(x)=4x(^3)-9x(^2)+6x-1 Find: a.) absolute minimum of f(x) on the interval [0,1]. b.) absolute maximum of f(x) on the interval [0,1].
f(x)=3tan(sqrt(x)). find f'(28) AND f(x)=ln(6+cox(9x)). find f'(8)
f(x)=3tan(sqrt(x)). find f'(28) AND f(x)=ln(6+cox(9x)). find f'(8)
Find f. f ''(x) = 6 + 6x + 24x2,    f(0) = 5,    f (1) = 13
Find f. f ''(x) = 6 + 6x + 24x2,    f(0) = 5,    f (1) = 13
Find f. f ''(x) = 6 + 6x + 36x2,    f(0) = 3,    f (1) = 13
Find f. f ''(x) = 6 + 6x + 36x2,    f(0) = 3,    f (1) = 13
Find the maximum and minimum values of f(x,y)= xy on the ellipse 9x^2+y^2 = 8.
Find the maximum and minimum values of f(x,y)= xy on the ellipse 9x^2+y^2 = 8.
f(x) =+x3−3x2+ 9x+ 13. Find an upper and a lower bound on the real zeros of(x).
f(x) =+x3−3x2+ 9x+ 13. Find an upper and a lower bound on the real zeros of(x).
Find f. f ''(x) = 8 + 6x + 36x2, f(0) = 5, f (1) =...
Find f. f ''(x) = 8 + 6x + 36x2, f(0) = 5, f (1) = 15
Find f(x). 1. f''(x) = (1/3) x^3 −3x^2 + 6x 2. f''(x) = −1 + 6x−12x^2,...
Find f(x). 1. f''(x) = (1/3) x^3 −3x^2 + 6x 2. f''(x) = −1 + 6x−12x^2,    f(0) = 4, f'(0) = 12 3. f'''(x) = sinx, f(0) = 1, f'(0) = 2, f''(0) = 3
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT