Question

find the equation of the tangent line when r=sqrt(sin0cos0) when
0(theta)=pi/4

Answer #1

What is the tangent line equation for the circle r = 2cos(theta)
when theta = pi/3?

Find the tangent line equation to the curve r=4-3sinx when
x=pi

Find all theta from (-pi,pi) for which the tangent line of
r=tan(theta/2) is horizontal.
I have gotten to
1/2sec^2(theta/2)*sin(theta)+tan(theta/2)*cos(theta)=0
How do I solve for 0?

1. Find the slope of the tangent line to
r=2+sin3Θ at the point where
Θ=pi/4 Θ=theta
2. Find the area of the region that lies inside the
curve r=4*sinΘ and outside the curve r=2

Write the equation ( in terms of x and y) of the tangent line to
the curve r = 2sintheta at theta = pi/3
y= ?
I keep getting y = (sqrt(3)/5) * (x - 0.1732050808) + 0.3

Consider the polar curve r = 2 cos theta. Determine the slope of
the tangent line at theta = pi/4.

let f(x) = sqrt x^4+4x+4.find the equation of the tangent line
to the graph of f −1(a) when a = 3

Consider the curve r = 2 - 3sin (theta). Give a vector
equation of the tangent line at theta = 0.

1.
Find the arclength of r=cos^(3)(theta/3)
2. Find the area outside r=3 and inside
r^2=18cos(2•theta)
3. Find the slope of the tangent line to r=2sin(4•theta) at
theta=pi/4

Find an equation of the tangent line to y=cosx at the point (3pi/4,
-sqrt(2)/2). Include hand sketched copy of tangent line and
graph

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