Question

Make two non-zero series, one convergent and one divergent, that we can use ratio test to...

Make two non-zero series, one convergent and one divergent, that we can use ratio test to conclude convergence and divergence, respectively. The series cannot be geometric series.

Homework Answers

Answer #1

which is the required answer

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Test the series for convergence or divergence. ∞ en n2 n = 1 convergent or divergent    
Test the series for convergence or divergence. ∞ en n2 n = 1 convergent or divergent    
We want to use comparison test in order to determine whether the series   is convergent or divergent....
We want to use comparison test in order to determine whether the series   is convergent or divergent. Which of the following is correct?
Are the series convergent or divergent. Use the direct comparison test. If direct comparison test cannot...
Are the series convergent or divergent. Use the direct comparison test. If direct comparison test cannot be used, use the limit comparison test. (a)∞∑n=1 2/(n^2−2) (b)∞∑n=2 1/((√n)−1 )
Use the RATIO test to determine whether the series is convergent or divergent. a) sigma from...
Use the RATIO test to determine whether the series is convergent or divergent. a) sigma from n=1 to infinity of (1/n!) b) sigma from n=1 to infinity of (2n)!/(3n) Use the ROOT test to determine whether the series converges or diverges. a) sigma from n=1 to infinity of    (tan-1(n))-n b) sigma from n=1 to infinity of ((-2n)/(n+1))5n For each series, use and state any appropriate tests to decide if it converges or diverges. Be sure to verify all necessary...
Use the ratio test to determine convergence or divergence. If the ratio test is inconclusive, use...
Use the ratio test to determine convergence or divergence. If the ratio test is inconclusive, use another method to determine convergence or divergence. ∞ (−1)n(n!)2 / (7n)! n = 1 Its the series from 1 to infinity of (-1)^n times (n!)^2 divided by (7n)!
Determine whether the given series is convergent or divergent. Show you work and state the theorem/test...
Determine whether the given series is convergent or divergent. Show you work and state the theorem/test you use. Σ (2)/(sqrt(n)+2) n=1 and upper infinity
Determine whether the given series is convergent or divergent. Show you work and state the theorem/test...
Determine whether the given series is convergent or divergent. Show you work and state the theorem/test you use. Σ(-1)^n (sqrt(n))/(2n+3) n=1 and upper infinity
(a) Use any test to show that the following series is convergent. X∞ n=1 (−1)n n...
(a) Use any test to show that the following series is convergent. X∞ n=1 (−1)n n 2 + 1 5 n + 1 (b) Find the minimum number of terms of the series that we need so that the estimated sum has an |error| < 0.001.
Use any test to show that the following series is convergent. X∞ n=1 (−1)n (n2+ 1/...
Use any test to show that the following series is convergent. X∞ n=1 (−1)n (n2+ 1/ 5n + 1) (b) Find the minimum number of terms of the series that we need so that the estimated sum has an |error| < 0.001.
1. To test the series ∞∑k=1 1/5√k^3 for convergence, you can use the P-test. (You could...
1. To test the series ∞∑k=1 1/5√k^3 for convergence, you can use the P-test. (You could also use the Integral Test, as is the case with all series of this type.) According to the P-test: ∞∑k=1 1/5√k^3 converges the P-test does not apply to ∞∑k=1 1/5√k^3 ∞∑k=1 1/5√k^3 diverges Now compute s4, the partial sum consisting of the first 4 terms of ∞∑k=1 1 /5√k^3: s4= 2. Test the series below for convergence using the Ratio Test. ∞∑n=1 n^5 /1.2^n...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT