Question

A basketball team sells tickets that cost $10,$20 or, for VIP seats, $30. The team has sold 535 tickets overall. It has sold 197 more $20 tickets than $10 tickets. The total sales are $9550. How many tickets of each kind have been sold?

Answer 1

Let, no of $10 tickets sold is x

Let, no of $20 tickets sold is y

Let, no of $30 tickets sold is z

Total no of tickets sold is 535 implies

No of $20 tickets is 197 more than $10 tickets implies

Substitute y in terms of x in the above equation implies

Total Sales is $9950 implies

Substitute y in terms of x in the above equaton implies

Eq1-Eq2 gives

Therefore, the value of y is

The value of z is

Hence, no of $10 tickets is 151, no of $20 tickets is 348, no of VIP Tickets is 36