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The half-life of krypton-91 (91Kr) is 10 s. At time t = 0 a heavy canister...

The half-life of krypton-91 (91Kr) is 10 s. At time t = 0 a heavy canister contains 7 g of this radioactive gas.

(a) Find a function

m(t) = m02−t/h  that models the amount of 91Kr remaining in the canister after t seconds.

(b) Find a function

m(t) = m0e−rt hat models the amount of 91Kr remaining in the canister after t seconds. (Round your r value to five decimal places.)

c) How much 91Kr remains after 1 min? (Round your answer to three decimal places.)

(d) After how long will the amount of 91Kr remaining be reduced to 1 µg (1 microgram, or 10−6 g)? (Round your answer to the nearest whole number.)

Math   Precalculus   
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