Question

log_2 5x= ?

Answer 1

you didnot upload full question

what to find for log₂(5x)

Let the solution for

log₂(5x) = y

by applying log rule: a = log_b(b^a)

similarly for y = log₂(2^y)

substitute back

log₂(5x) = log₂(2^y)   since both side logs are same with same base so it is equal to

5x = 2^y

Therefore log₂(5x) is equivalent to

5x = 2^y

If your problem find out the inverse of log₂(5x) then it is follow:

If a function f (x) is mapping x to y,then the inverse function of f(x)maps y back to x.

now the solution for log₂(5x) is

5x = 2^y

Interchange the variables x and y

5y = 2^x

now y = 2^x / 5

Therefore Inverse of   log₂(5x) is y = 2^x / 5