In triangle ABC, angle A measures 33 degrees. If angle C measures 38 degrees and BC has length 12, find AB.
a) 12sin38/sin33
b)12sin(38/33)
c)6
d)12sin33/sin38
e)6sqrt3
Sine formula
Let ABC be a triangles with sides BC = a , CA = b and AB = c
We have = =
Given BC = a = 12 and let AB = c
And A = 330 , C = 380
From the sine formula, we have
=
=
Thus, c = AB =
Thus, option 'a' is the correct answer.
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