Find the complete solution to
[1 2 2 1]
[1 3 4 5]
[0 1 2 4]
x= [0]
[3]
[3]
reducing the matrix to reduced row echelon form
x1 - 2x3- 7x4 = -6
x2 + 2x3 + 4x4 = 3
x3 = x3
x4 = x4
solution is
(x1 , x2 , x3 , x4 ) = ( -6 + 2s+ 7t , 3 - 2s - 4t , 0 + 1s , 0 + 1t )
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