f f(x)= 4x?1 if ?4?x?4 and x3?4 if 4<x?5 ?, ?find: (a)? f(0), (b)? f(1), (c) ?f(44?), (d) f(5)
Given,
f(x) = 4x-1 if ?4?x?4...........(1)
f(x) = x3-4 if 4<x?5........(2)
a) f(0), as 0 lies in 1st interval,
we use, f(x) = 4x-1
implies, f(0) = 4(0)-1 = -1
f(0) = -1
b) f(1), as 1 lies in 1st interval,
we use, f(x) = 4x-1
implies, f(1) = 4(1)-1 = 3
f(1) = 3
c) f(44) ........ I am asuuming there is an error in question as the function is not defined for x =44. So,
taking f(4) which is under 1st intervel of ?4?x?4
So, f(4) = 4X4 -1 = 15
d) f(5) , x = 5 is under the interval 4<x?5.
So, f(x) = x3-4
f(5) = 53-4 = 125-4 = 121
f(5) = 121
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