Question

solve the initial value problem: 2x-3e^(3x)y-e^(3x)y'=0 y(0)=2

Answer #1

Solve the initial value problem y = 3x^2 − 2y, y(0) = 4

Solve the initial value problem y' = 3x^2 − 2y, y(0) = 4

Solve the following initial value problem.
y′′ − 9y′ + 20y = 3x +
e5x, y(0)
= 0, y′(0) = 2

Solve the initial value problem
x′=−3x−y,
y′= 13x+y,
x(0) = 0,
y(0) = 1.

Solve the initial-value problem.
(x2 + 1)
dy
dx
+ 3x(y − 1) = 0,
y(0) = 4

Solve the following initial value problem. y(4) − 6y′′′ + 5y′′
= 2x, y(0) = 0, y′(0) = 0, y′′(0) = 0, y′′′(0) = 0.
(not using Laplace)

solve the initial value problem using Laplace
transform
x"(t)+3x'(t)+2x(t)=t
x(0)=0
x'(0)=2
differntial equations

Use Laplace Transform to solve the initial value
problem
x''+2x'+2x=e-t x(0)=x'(0)=0.

Solve the initial value problem: y''−2y'+y=e^t/(1+t^2), y(0) =
1, y'(0) = 0.

Solve the given LDE using the method of undetermined
coefficients. y'''-y'=4e^-x+3e^2x; y(0)=0, y'(0)=-1,
y''(0)=2

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