Question

Solve 6cos2(t)+sin(t)−4=06cos2(t)+sin(t)-4=0 for all solutions 0≤t<2π0≤t<2π

Answer #1

we are given

we can use trig identity

we can multiply both sides by -1

we can solve for t

we can use unit circle

and we get

so, we get

**...........Answer**

Solve 8cos2(x)+2cos(x)−3=08cos2(x)+2cos(x)-3=0 for all solutions
0≤x<2π0≤x<2π
and
Solve 6sin2(w)−cos(w)−5=06sin2(w)-cos(w)-5=0 for all solutions
0≤w<2π0≤w<2π

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A = √7474, sin B = √91109110, and cos B = 310310.
cos(A−B)cos(A-B) =
3,
Find all solutions of the equation 2cosx−1=02cosx-1=0 on
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The answers are A and B, where A<BA<B
A=? B=?

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on the interval 0≤α<2π0≤α<2π
αα =
Give your answers accurate to at least 3 decimal places, as a list
separated by commas
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on the interval 0≤w<2π0≤w<2π
ww =
Give your exact solutions if appropriate, or solutions accurate to
at least 3 decimal places, as a list separated by commas
3.Solve 7sin(2β)−2cos(β)=07sin(2β)-2cos(β)=0 for all solutions
0≤β<2π0≤β<2π
ββ =
Give exact answers or answers accurate to 3 decimal places, as
appropriate
4.Solve...

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solutions.Give your answers accurate to at least two decimal
places, as a list separated by commas
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solutions
4.Solve for tt, 0≤t<2π0≤t<2π
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2sec2(x)=3−tan(x)
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csc (2x)-9=0
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(a) At what positions does ‖r′(t)‖ have maximum and minimum
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(b) At what positions does the curvature have maximum and
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(Enter your answers as a comma-separated list.)
cot(x) + 4 = 5
x=

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