Let the function f be defined by y= f (x), where x and f (x) are real numbers. Find f (2), f (-3), f (k), and f (k^2-1)
f(x) = 2/3 x + 5
f(x)= 2/3 x +5. For f(2), write 2 for x, in f(x). Accordingly,
f(2)= 2/3 (2) +5 = 4/3 +5 = 19/3
Likewise,
f(-3)= 2/3 (-3) +5= -2 +5= 3
f(k)= 2/3 k +5
f(k2 -1)= 2/3 (k2 -1) +5= 2/3 k2 -2/3 +5 = 2/3 k2 +13/3
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